SOLUTION: Please help Graph- f(x)=x^2-3

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Question 55091: Please help Graph- f(x)=x^2-3
Found 2 solutions by rchill, funmath:
Answer by rchill(405) About Me  (Show Source):
You can put this solution on YOUR website!
That should graph to a parabola as it is a polynomial of 2nd degree. To plot it, you can use a graphing calculator (there are several free ones online), or you can use the discriminant formulas, or you can just use various values of x to solve for y. The graph is:
graph%28200%2C200%2C-5%2C5%2C-5%2C5%2Cx%5E2-3%29

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Graph- f%28x%29=x%5E2-3
This is a parabola in standard form: highlight%28f%28x%29=ax%5E2%2Bbx%2Bc%29%29.
We can find the axis of symmetry by this formula: highlight%28x=-b%2F2a%29
Our a=1, b=0, c=-3
The axis of symmetry: x=-%280%29%2F2%281%29 x=0 (Note this is the x value of the vertex.)
We use the axis of symmetry to intelligently pick points to plot:
Plot (-1,f(-1)), (0,f(0)), and (1,f(1))
Let x=-1: f(-1)=(-1)^2-3=1-3=-2. Plot (-1,-2)
Let x=0: f(0)=(0)^2-3=0-3=-3. Plot (0,-3) (vertex)
Let x=1: f(1)=(1)^2-3=1-3=-2. Plot (1,-2)
Connect the dots and you get:
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2Cx%5E2-3%29
Happy Calculating!!!