SOLUTION: A small beach ball has a radius of 8 inches. A larger beach ball has a volume that is twice the volume of the small ball. What is the best approximation for the radius of the large

Algebra ->  Graphs -> SOLUTION: A small beach ball has a radius of 8 inches. A larger beach ball has a volume that is twice the volume of the small ball. What is the best approximation for the radius of the large      Log On


   

Question 537539: A small beach ball has a radius of 8 inches. A larger beach ball has a volume that is twice the volume of the small ball. What is the best approximation for the radius of the large beach ball?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A small beach ball has a radius of 8 inches. A larger beach ball has a volume that is twice the volume of the small ball. What is the best approximation for the radius of the large beach ball?
:
Let r = radius of the large ball
:
4%2F3*pi%2Ar%5E3 = 2(4%2F3*pi%2A8%5E3)
Multiply both sides by 3, to get rid of the denominators, find 8^3
4(pi%2Ar%5E3) = 8(pi%2A512)
divide both sides by 4%2Api, results
r^3 = 2(512)
r^3 = 1024
r = 3sqrt%281024%29; (cube root)
r = 10.08 inches, radius of the larger
:
:
Check this on a calc
(4/3)*pi*8^3 = 2144.66 cu in
(4/3)*pi*10.08^3 = 4290.12, close enough