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Question 53653This question is from textbook
: HELP!! I am stumped.
Determine the center and radius of each circle and sketch the graph.
#28. x squared + (y-2)squared =16
Determine the center and radius of each circle and sketch the graph.
#50. x squared + 10x +y squared - 8y = -40
Find the slope of each line described.
#58. a line parallel to 3x-9y=4
Write an equation in standard from using only intergers for each of the lines described. In each case make a sketch.
#60. A line perpendicular to 2x-3y=8
#64 The line with the slope -3, going through (-3,4)
This question is from textbook
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Determine the center and radius of each circle and sketch the graph.
#28. x squared + (y-2)squared =16
This follows the form (x-h)^2 + (y-k)^2=r^2
h=0, k=2 so the center is at (0,2)
r=4
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Determine the center and radius of each circle and sketch the graph.
#50. x squared + 10x +y squared - 8y = -40
(x^2+10x+?)+(y^2-8y+?)=-40+?
Complete the square on each term of left side.
(x^2+10x+25)+(y^2-8y+16)=-40+25+16
(x+5)^2+(y-4)^2=1
Center at (-5,4); radius=1
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Find the slope of each line described.
#58. a line parallel to 3x-9y=4
The slope of the given line is 1/3
A parallel line must have the same slope; for example y=(1/3)x
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Write an equation in standard from using only integers for each of the lines described. In each case make a sketch.
#60. A line perpendicular to 2x-3y=8
The given line has slope m=2/3; the perpendicular line must have slope -3/2
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#64 The line with the slope -3, going through (-3,4)
y=mx+b
4=-3(-3)+b
b=-5
EQUATION: y=-3x-5
Cheers,
Stan H.
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