SOLUTION: Find the x and y-intercepts of the function: y= x^2 + 4x - 1. I found y=-1 but I can't figure out how to solve for the x-intercept. Please help!
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Question 53506: Find the x and y-intercepts of the function: y= x^2 + 4x - 1. I found y=-1 but I can't figure out how to solve for the x-intercept. Please help! Answer by mathchemprofessor(65) (Show Source):
You can put this solution on YOUR website! y= x^2 + 4x - 1
Answer:
If x=0, then y=-1
If y=0, we get a quadratic equation,
x^2 + 4x - 1=0
Solve for x, using quadratic formula
x = (-b +- sqrt( b^2-4*a*c ))/(2*a)
You'll get the x intercept.
