You can put this solution on YOUR website! y= 2x lx-3l+4
How do you find the x intercepts?
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To find the x-intercepts, set y=0, then solve for x.
For (x-3)>0
2x lx-3l+4=0
2x^2-6x+4=0
x^2-3x+2=0
(x-2)(x-1)=0
x=2
x=1
Both solutions are rejected as they cannot satisfy the equation because of +4 in the equation.
..
For(x-3)<0
2x l-(x-3)l+4=0
-2x^2+6x+4=0
2x^2-6x-4=0
solve by quadratic formula as follows:
a=2, b=-6, c=-4
x=[-(-6)±√((-6)^2-4*2*-4)]/2*2
x=[6±√(36+32)]/4
x=[6±√68]/4
x=(6±8.2462)/4
x=3.5616 (This solution is also rejected for the same reason as solutions 2 and 1 above.
or
x=-.5616
check:
2(-.5616)|-.5616-3|+4=0
solution:
x-intercept=-.5616
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