SOLUTION: I need help graphing x^2 + y^2 +2x -2y= 2 I also need to find the intercepts

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Question 48281: I need help graphing x^2 + y^2 +2x -2y= 2
I also need to find the intercepts
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + y^2 + 2x - 2y = 2
x^2 + 2x + y^2 - 2y = 2
(x + 1)^2 + (y - 1)^2 = 2 + 1 + 1 = 4
(x + 1)^2 + (y - 1)^2 = 4
Circle with radius of 2 units and center at (-1,1).

x-intercepts:
x^2 + 2x + y^2 - 2y = 2
x^2 + 2x + 0^2 - 2(0) = 2
x^2 + 2x - 2 = 0
x+=+%28-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-2+%2B-+sqrt%28+4+%2B+8+%29%29%2F%282%29+
x+=+%28-2+%2B-+2%2Asqrt%28+3+%29%29%2F%282%29+
x+=+-1+%2B-+sqrt%283%29+
P(+-1+%2B+sqrt%283%29+,0) and P(+-1+-+sqrt%283%29+,0)
y-intercept:
x^2 + 2x + y^2 - 2y = 2
0^2 + 2(0) + y^2 - 2y = 2
y^2 - 2y - 2 = 0
x+=+%28-b+%2B-+sqrt%28+b%5E2+-+4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%282+%2B-+sqrt%28+4+%2B+8+%29%29%2F%282%29+
x+=+%282+%2B-+2%2Asqrt%28+3+%29%29%2F%282%29+
x+=+1+%2B-+sqrt%28+3+%29+
P(0,+1+%2B+sqrt%283%29+) and P(0,+1+-+sqrt%283%29+)