Question 47977: I don't understand how you can graph the lines 6y=2x+12 and 6x=2y-8 on a coordinate plane. Can someone please help me?
Found 2 solutions by stanbon, tutorcecilia:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! graph the lines
1st: 6y=2x+12 and
2nd: 6x=2y-8
1st: Let x=0, then y=2 giving you the point (0,2)
Let x=2, then y=16 giving you the point (2,16)
Plot these two points and draw a line through them.
2nd: Let y=0, then x=-4/3 giving you the point (-4/3,0)
Let y=4, then x=0 giving you the point (0,4)
Plot these two points and draw a line through them.
Cheers,
Stan H.
Answer by tutorcecilia(2152)  (Show Source):
You can put this solution on YOUR website! 6y=2x+12 [Re-write in the slope-intercept formate (y=mx+b)]
6y/6=2x/6+12/6 [Solve for "y"]
y = (1/3)x + 2 [Graph]
y = any value for "y" on the line
m = the slope = (1/3)
x = any corresponding value for "x" on the line
b = the y-intercept; where the line crosses the y-axis = (2)
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6x=2y-8 [Re-write in the slope-intercept formate (y-mx+b)]
6x+8=2y-8+8 [Solve for "y"]
6x+8=2y
6x/2+8/2=2y/2
3x+4=y [Re-arrange the equation]
y = 3x+4 [Graph]
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Points of interception: (-3/4, 7/4) [Points in common]
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