SOLUTION: Please help me solve this equaation f(x)= x^2-12x-6

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Question 471238: Please help me solve this equaation f(x)= x^2-12x-6
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
x2-12x-6=0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-12x%2B-6+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-12%29%5E2-4%2A1%2A-6=168.

Discriminant d=168 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--12%2B-sqrt%28+168+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-12%29%2Bsqrt%28+168+%29%29%2F2%5C1+=+12.4807406984079
x%5B2%5D+=+%28-%28-12%29-sqrt%28+168+%29%29%2F2%5C1+=+-0.48074069840786

Quadratic expression 1x%5E2%2B-12x%2B-6 can be factored:
1x%5E2%2B-12x%2B-6+=+1%28x-12.4807406984079%29%2A%28x--0.48074069840786%29
Again, the answer is: 12.4807406984079, -0.48074069840786. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-12%2Ax%2B-6+%29
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