SOLUTION: the equation of the line passing through (-1,2) and perpendicular to y=3x=4

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Question 468148: the equation of the line passing through (-1,2) and perpendicular to y=3x=4
Answer by Gogonati(855) About Me  (Show Source):
You can put this solution on YOUR website!
As we know two lines are perpendicular if and only if their slopes are negative
reciprocals of one another m%5B1%5D=-1%2Fm%5B2%5D or m%5B1%5D%2Am%5B2%5D=-1
Since the equation of one line is y=3x-4, its slope is m%5B1%5D=3
The slope of the perpendicular line will be 3%2Am%5B2%5D=-1<=> m%5B2%5D=-1%2F3
Now we write the equation of the line that passes through (-1, 2), and has the
slope m%5B2%5D=-1%2F3: y-2=-1/3(x+1), converting it in the standard form we get:
3y-6=-x-1 <=> x+3y=5 or in slope-intercept form y=-%281%2F3%29x%2B5%2F3.