SOLUTION: solve for x. x^2+13=6x

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Question 443754: solve for x. x^2+13=6x
Answer by swincher4391(1107) About Me  (Show Source):
You can put this solution on YOUR website!
Let's complete the square here:
x%5E2+-6x+=+-13
Remember complete the square by adding %28b%2F2%29%5E2 to both sides.
x%5E2+-6x+%2B9+=+-13+%2B+9
This works because now you can factor the left into %28x-%28b%2F2%29%29%5E2 always.
%28x-3%29%5E2+=+-4
x-3+=+sqrt%28-4%29
sqrt%28-4%29 does not exist in real numbers.
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If you are not working with imaginary numbers, you would say no real solutions:
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If you are allowed to work with them, read on.
x-3++=+0%2B-+2i
x+=+3%2B-+2i