SOLUTION: Solve by graphing and then get an exact solution by using either substitution or elimination. (if you cant graph please just answer the second part)
y=2/3x+3
{
3x-3y=-6
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-> SOLUTION: Solve by graphing and then get an exact solution by using either substitution or elimination. (if you cant graph please just answer the second part)
y=2/3x+3
{
3x-3y=-6
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Question 428586: Solve by graphing and then get an exact solution by using either substitution or elimination. (if you cant graph please just answer the second part)
y=2/3x+3
{
3x-3y=-6 Answer by Theo(13342) (Show Source):
in order to graph these equations, you need to solve for y.
the first one is already solved for y.
the second one is solved for y in the following manner:
3x - 3y = -6
subtract 3x from both sides of the equation to get:
-3y = -3x - 6
divide both sides of the equation by -3 to get:
y = (-3/-3)*x - (6/-3)
simplify this to get:
y = x - (-2)
simplify further to get:
y = x + 2
the 2 equations that you can now graph are:
y = (2/3)x + 3
y = x + 2
the graph of these equations is shown below:
the graph shows an intersection at somewhere around x = 3 and y = 5.
you can solve these equations by substitution to see if the answer comes out somewhere near there.
use the original equations of:
y = (2/3)x + 3
3x - 3y = -6
since your first equation has already solved for y, you can use that to substitute for y in the second equation to get:
3x - 3y = -6 becomes 3x - 3*((2/3)x + 3) = -6
simplify by removing parentheses to get:
3x - 3*(2/3)x - 3*3 = -6
simpify further to get:
3x - 2x - 9 = -6
combine like terms to get:
x - 9 = -6
add 9 to both sides of the equation to gert:
x = -6 + 9
simplify further to get:
x = 3
you now have x = 3 and you can substitute for x in either equation to solve for y.
we'll use the first equation.
the first equation is y = (2/3)x + 3
substitute 3 for x to get:
y = (2/3)*3 + 3
simplify to get:
y = 2 + 3 which becomes y = 5
your solution for this set of simultaneous equations is:
