SOLUTION: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46.

Algebra ->  Graphs -> SOLUTION: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46.      Log On


   

Question 42645: Find two consecutive integers such that the sum of 2 times the first integer and 4 times second integer is 46.
Answer by Socom491(19) About Me  (Show Source):
You can put this solution on YOUR website!
Let n= First Integer
Let n+1= Second Integer
2n%2B4%28n%2B1%29=46
2n%2B4n%2B4=46
6n%2B4=46
++-4=-4
6n=42
6n%2F6=42%2F6
n=7
Now we plug 7 into the n statements,
so the first number is 7 and the second is 8.