SOLUTION: How do I simplify the trinomial 3x^2+10x+3 into a binomial?

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Question 423054: How do I simplify the trinomial 3x^2+10x+3 into a binomial?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming you mean factor into a product of binomials.




Looking at the expression 3x%5E2%2B10x%2B3, we can see that the first coefficient is 3, the second coefficient is 10, and the last term is 3.


Now multiply the first coefficient 3 by the last term 3 to get %283%29%283%29=9.


Now the question is: what two whole numbers multiply to 9 (the previous product) and add to the second coefficient 10?


To find these two numbers, we need to list all of the factors of 9 (the previous product).


Factors of 9:
1,3,9
-1,-3,-9


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 9.
1*9 = 9
3*3 = 9
(-1)*(-9) = 9
(-3)*(-3) = 9

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 10:


First NumberSecond NumberSum
191+9=10
333+3=6
-1-9-1+(-9)=-10
-3-3-3+(-3)=-6



From the table, we can see that the two numbers 1 and 9 add to 10 (the middle coefficient).


So the two numbers 1 and 9 both multiply to 9 and add to 10


Now replace the middle term 10x with x%2B9x. Remember, 1 and 9 add to 10. So this shows us that x%2B9x=10x.


3x%5E2%2Bhighlight%28x%2B9x%29%2B3 Replace the second term 10x with x%2B9x.


%283x%5E2%2Bx%29%2B%289x%2B3%29 Group the terms into two pairs.


x%283x%2B1%29%2B%289x%2B3%29 Factor out the GCF x from the first group.


x%283x%2B1%29%2B3%283x%2B1%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x%2B3%29%283x%2B1%29 Combine like terms. Or factor out the common term 3x%2B1


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Answer:


So 3x%5E2%2B10x%2B3 factors to %28x%2B3%29%283x%2B1%29.


In other words, 3x%5E2%2B10x%2B3=%28x%2B3%29%283x%2B1%29.


Note: you can check the answer by expanding %28x%2B3%29%283x%2B1%29 to get 3x%5E2%2B10x%2B3 or by graphing the original expression and the answer (the two graphs should be identical).


If you need more help, email me at jim_thompson5910@hotmail.com

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Jim