SOLUTION: Tell weather the parabola opens up or down and find the coordinates of the vertex and the axis of symmetry y=-x^2-4x+2
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Question 420248: Tell weather the parabola opens up or down and find the coordinates of the vertex and the axis of symmetry y=-x^2-4x+2 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Tell weather the parabola opens up or down and find the coordinates of the vertex and the axis of symmetry y=-x^2-4x+2
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y=-x^2-4x+2
Your questions can be answered after we change equation to standard form:
y=(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.
completing the square to convert to standard form,
y=-(x^2+4x+4)+2+4
y=-(x+2)^2+6
This parabola opens downward because the coefficient of x^2 is negative. If the coefficient is positive, it will open upwards.
The coordinates of the vertex are (-2,6)
The axis of symmetry: x=-2
See what the graph looks like below:
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