SOLUTION: Determine the vertex of y=x^2-8x+22 I have D(4,8) is this correct? Thank you.

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Question 42015This question is from textbook
: Determine the vertex of y=x^2-8x+22
I have D(4,8) is this correct? Thank you. This question is from textbook

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
This is a parabola that opens upward, and the vertex (minimum point) will be at x=%28-b%29%2F%282a%29. In this case, vertex is at x=+%288%29%2F%282%29=4.

If x = 4, then y = 4^2 - 8*4 +22 = 16 - 32 +22=6.

I get a vertex of (4, 6) . Check it out with the graph:

graph%28300%2C300%2C+-6%2C10%2C+-4%2C+24%2C+x%5E2-8x%2B22%29

R^2 at SCC