Question 419197: graph the equation using the slope and the y-intercept.
y=5/3x+8
Found 2 solutions by algebrahouse.com, Edwin McCravy:
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! "graph the equation using the slope and the y-intercept.
y = 5/3x + 8"
Slope-intercept form is y = mx + b
m is the slope
b is the y-intercept
In y = 5/3x + 8
slope = 5/3
y-intercept = 8
To graph:
- start by putting a point on 8 on the y-axis, that is the y-intercept
- from there, go up 5 and to the right 3, and put another point (since the slope is 5/3....rise/run}
- draw a line through the two points
www.algebrahouse.com
Answer by Edwin McCravy(20055)  (Show Source):
You can put this solution on YOUR website! graph the equation using the slope and the y-intercept.
Compare that equation to
and you'll see that m = the slope =  and b=8 and the
y-intercept is the point (0,b) = (0,8). We plot the y-intercept,
(0,8):
Starting at that y-intercept we take the NUMERATOR of the slope,
which is 5, and draw a VERTICAL line 5 units long UPWARD, since
the slope is positive (it would be downward if the slope were
negative), like the green arrow below:
Now from that arrowhead, we turn RIGHT and draw a HORIZONTAL line
equal to the number of units indicated by the DENOMINATOR of the slope,
that is, 3 units, like the green horizontal line below:
To make the graph, we draw a line through the end of the horizontal
line and the y-intercept (0,8), like this:
That red line is the graph of the equation .
Edwin
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