SOLUTION: solve by the elimination method 0.3x-0.2y=4 0.4x+0.1y=49/23

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Question 414953: solve by the elimination method
0.3x-0.2y=4
0.4x+0.1y=49/23

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
0.3x-0.2y=4.......
0.3x%2F0.2-4%2F0.2=y
1.5x-20=y

0.4x%2B0.1y=49%2F23 ...I guess you have 0.1y
0.4x%2B0.1y=2.13

0.4x%2F0.1-2.13%2F0.1=y
4x-21.3=y

----------------
1.5x-20=y...........1
-
4x-21.3=y ...............2...subtract 2 from 1
-----------------------------------------
1.5x-4x-20%2B21.3=y-y
-2.5x+1.3=+0
+1.3=+2.5x
+1.3%2F2.5=+x
+0.52+=+x .........now find y
1.5x-20=y...........1
1.5%280.52%29-20=y
0.78-20=y

-19.22+=+y

check:
4x-21.3=y ...............2
4%280.52%29-21.3=-19.22
2.08-21.3=-19.22
-19.22=-19.22


+graph%28+500%2C+500%2C+-15%2C+25%2C+-25%2C25%2C+1.5x-20%2C+4x-21.3%29+