SOLUTION: the perimeter of a rectangle is 234 inches. the length exceeds the width by 65 inches. find the length and the width.

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Question 414948: the perimeter of a rectangle is 234 inches. the length exceeds the width by 65 inches. find the length and the width.

Answer by praseenakos@yahoo.com(507) About Me  (Show Source):
You can put this solution on YOUR website!
suppose, width = x inches
===> length = x + 65 inches
Perimeter = 2(length+ width)

==> 234 = 2( x + x + 65 )

==> 234 = 2( 2x + 65 )
==> 234%2F2++=+2x+%2B+65+
==> +117+=+2x+%2B+65+
==> +117-+65+=+2x+
==> +52+=+2x
==> +52%2F2+=+2x%2F2

==> +26++=+x

width+=+26+inches
length+=++26+%2B+65+=+91+inches+