SOLUTION: the area of a rectangular field is 2k^2 + 27k +70 feet, the width is k + 10 feet what is the length in feet of the field. tried to cancell out the ks but that didn't work. i'm jus

Algebra ->  Graphs -> SOLUTION: the area of a rectangular field is 2k^2 + 27k +70 feet, the width is k + 10 feet what is the length in feet of the field. tried to cancell out the ks but that didn't work. i'm jus      Log On


   



Question 414266: the area of a rectangular field is 2k^2 + 27k +70 feet, the width is k + 10 feet what is the length in feet of the field. tried to cancell out the ks but that didn't work. i'm just confused
Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!

2k^2 + 27k + 70
= 2k^2 + 20k +7k +70
=2k(k+10) +7(k+10)
=(2k+7)(k+10)
area = length * width
if width is k+10, then length is 2k+7 ....