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Question 412812: I decided to not choose not any of the chioces from the topics so i only chose
Test because the others did not show how to find the fixed perimeter in a table.
My question asks How do you find the the fixed perimeter for the table on the right. It's a parabala table from a graph which is shaped like a hill, curving
up then curving down. in the middle i think is the maximum or the vertex (correct me if i'm wrong). Later it says find an equation for the graph
yet i dont really know how the equation formula is (y=mx+b).may you also explain simply so i know or understand how to do this? (very simply please)
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Length m / Area m2
0 0
1 7
2 12
3 15
4 16
5 15
6 12
7 7
8 0
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
The area of a rectangle is given by multiplying the length times the width. Therefore, if you know the length and the area, you can find the width by dividing the area by the length.
The perimeter is given by multiplying the length by 2 and adding that to the width multiplied by 2.
So, all you have to do is, starting with the second line in your table, divide the number in the second column by the number in the first column. Multiply the result of your division by 2 and add that to the number in the first column multiplied by 2. Except for the first and last entries in the table, you should get the same answer every time, and that is your fixed perimeter.
The table gives you a set of points ) where the number in the first column is the  value and the number in the second column is the  value. Plot your set of points and draw a smooth curve. It should look like this when you are done:
But you should only graph the part that is in the first quadrant. The highest point in the graph, namely the point ) is the vertex. In this particular case, because you have a parabola (notice the spelling -- mine is correct) that opens downward, the vertex is a local maximum of the function.
John
My calculator said it, I believe it, that settles it
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