SOLUTION: I can't figure out y=mx+b I think I forgot how to solve this. x+3y=6 then I have have to put it back and shade one side of the graph.

Algebra ->  Graphs -> SOLUTION: I can't figure out y=mx+b I think I forgot how to solve this. x+3y=6 then I have have to put it back and shade one side of the graph.      Log On


   



Question 410685: I can't figure out y=mx+b I think I forgot how to solve this. x+3y=6 then I have have to put it back and shade one side of the graph.
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
x+3y=6 OR y = (-1/3)x + 2


y = (-1/3)x + 2 | slope m = -1/3 and y-intercept is Pt(0,2)
m = -1/3: as y increases/decreases by 1, x increases/decreases by 3 in opposite direction.
due to the equal sign, the graph is a Line..doesn't call for shading


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I can't figure out y=mx+b I think I forgot how to solve this. x+3y=6 then I have to put it back and shade one side of the graph.
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If you are shading, you have an inequality.
----
Let's assume you have x+3y < 6.
----
Then y < (-x/3) + 2
-------
Notice: No inequality is graphed directly.
You 1st must graph the boundary, which is
always an equality.
So, for your problem you should graph
y EQUALS (-x/3)+2 as a dashed line; dashed
because that boundary is not part of the
solution.
---
Then, since you want y LESS than (-x/3)+2
you should shade the half plane BELOW
the boundary to get:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cy%3C%28-x%2F3%29%2B2%29
-------------------
Cheers,
Stan H.
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