Question 40294: "Use the discriminant to find the number of the x-intercepts of the graph of the function y=-13x^2+2x+6."
Found 2 solutions by stanbon, mbarugel:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! "Use the discriminant to find the number of the x-intercepts of the graph of the function y=-13x^2+2x+6."
a=-13; b=2; c=6
Discriminant = b^2-4ac= 4-4*(-13)*(6)>0
Therefore there are two points at which
the curve intersects the Real Number x-axis.
cheers,
Stan H.
Answer by mbarugel(146) (Show Source):
You can put this solution on YOUR website! Hello!
In a quadratic equation of the form:
 ,
the formula for the discriminant is
In your case, we have a = -13, b=2, c=6. Therefore, the discriminant is:
2^2 - 4*(-13)*6 = 316
Since the discriminant is greater than zero, the graph has two x-intercepts. If it had been equal to zero, the graph would have had only one x-intercept. And, if it had been smaller than zero, the graph would have had no x-intercepts.
I hope this helps!
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