SOLUTION: can you help me? find the illegal values of c in the multiplcation statement {{{(c^2-3c-10)/(c^2+5c-14)}}}*{{{(c^2-c-2)/(c^2-2c-15)}}}

Algebra ->  Graphs -> SOLUTION: can you help me? find the illegal values of c in the multiplcation statement {{{(c^2-3c-10)/(c^2+5c-14)}}}*{{{(c^2-c-2)/(c^2-2c-15)}}}      Log On


   

Question 40082: can you help me?
find the illegal values of c in the multiplcation statement %28c%5E2-3c-10%29%2F%28c%5E2%2B5c-14%29*%28c%5E2-c-2%29%2F%28c%5E2-2c-15%29
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Once again, denominators cannot be zero, so we have to see what values of c make that so...those values are the "illegal" ones...so for
c^2 + 5c - 14 = 0
(c+7)(c-2) = 0
c = -7 or c = 2 and for
c^2 - 2c - 15 = 0
(c-5)(c+3) = 0
c = 5 or c = -3
Thus c is not allowed to be any of
-7, 2, 5, or -3