SOLUTION: needing help.. multiply {{{(r^2+7r+10)/(3)}}} by {{{(3r-30)/(r^2-5r-50)}}}
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Question 40081
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needing help..
multiply
by
Answer by
fractalier(6550)
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Always...factor and cancel, factor and cancel....so from
(r^2+7r+10)/3 * (3r-30)/(r^2-5r-50) we get
(r+2)(r+5) / 3 * 3(r-10) / (r-10)(r+5) now look what cancels...we get only...
r+2