SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. {{{f(x)=-2x^2+2x+1}}} The x-coordinate of the vertex is ___

Algebra ->  Graphs -> SOLUTION: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function. {{{f(x)=-2x^2+2x+1}}} The x-coordinate of the vertex is ___      Log On


   



Question 396135: Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function, and graph the function.
f%28x%29=-2x%5E2%2B2x%2B1
The x-coordinate of the vertex is ____.
(Type a simplified fraction.)
The y-coordinate of the vertex is ____.
(Type a simplified fraction.)
The equation of the line of symmetry is x=____.
(Type a simplified fraction.)
The maximum/minimum of f(x) is ____.
(Type a simplified fraction.)
The value, f%281%2F2%29=3%2F2 is a minimum or maximum?
Graph.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
The x-coordinate of the vertex of a parabola in the form f%28x%29=ax%5E2%2Bbx%2Bc is given by -b%2F2a.

The y-coordinate is then f%28-b%2F2a%29.

The line of symmetry passes through the vertex, so the equation is x=-b%2F2a.

The maximum or minimum is the value of the function at -b%2F2a. Whether it is a maximum or minimum depends on whether the parabola opens up or down. If it is concave up (makes a valley rather than a hill), the point is a minimum, otherwise it is a maximum. You can tell which way the parabola opens by the sign on the lead coefficient. if a%3C0, it is concave down, if a%3E0, it is concave up, and, of course, if a=0 you don't have a parabola at all.

Let's look at your specific problem:

f%28x%29+=+-2x%5E2%2B2x%2B1+

First thing to note is that a%3C0, so this is a concave down parabola and the vertex is a maximum.

-b%2F2a=-2%2F%282%28-2%29%29=1%2F2, so the x-coordinate of the vertex is 1%2F2 and the equation of the line of symmetry is x=1%2F2.

The value of the function at -b%2F2a, denoted f%28-b%2F2a%29 for your problem is f%281%2F2%29=-2%281%2F2%29%5E2%2B2%281%2F2%29%2B1+=+%28-1%2F2%29%2B1%2B1=3%2F2
So the y-coordinate of the vertex and the maximum value of f is 3%2F2