SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
{{{f(x)=(1/5)(x+4)^2+8}}}
The vertex is ____.
(Type an ordered pair.)
The
Algebra ->
Graphs
-> SOLUTION: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
{{{f(x)=(1/5)(x+4)^2+8}}}
The vertex is ____.
(Type an ordered pair.)
The
Log On
Question 394988: Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph the function.
The vertex is ____.
(Type an ordered pair.)
The line of symmetry is x=____.
The maximum/minimum value of f(x) is ____.
Is the value, f(-4)=8, a minimum or maximum?
Graph. Answer by ewatrrr(24785) (Show Source):
Hi
Using the vertex form of a parabola, where(h,k) is the vertex vertex is Pt(-4,8) Line of symmetry x = -4
minimum value of f(x) = 8
Vertex (-4,8) is a minimum |parabola opens upward as a = 1/5 > 0
