Hi
graphing first
y = x^2 - 2x + 1 y-intercept (when x=0) = (0,1)
Vertex form found by completing square
y = (x-1)^2 vertex is (1,0)
the vertex form of a parabola, 
where(h,k) is the vertex
then shading the 'inner portion' for y>x^2 - 2x + 1
(parabola itself not included)
