SOLUTION: graph f(x)=-x^2+4x-3, labeling the y-intercept, vertex, and axis of symmetry please help.

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Question 390281: graph f(x)=-x^2+4x-3, labeling the y-intercept, vertex, and axis of symmetry
please help.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,        

f(x)=-x^2+4x-3 

y-intercept when x = 0  Pt(0-3)

x-intercept when y = 0

y = -x^2 + 4x - 3 = 0   Completing Square to put into vertex form

y = -[x^2 - 4x] - 3 = 0

y = -[(x-2)^2 - 4] - 3 = 0

y = -(x-2)^2 + 4 - 3 = 0  Vertex Pt (2,1)  axis of symmetry is x = 2