Question 389989: Graph the solution set of x³+x²<2x
Answer by robertb(5830)   (Show Source):
You can put this solution on YOUR website!  ===>  ===> x(x+2)(x-1) < 0. The critical numbers of the inequality are -2, 0, and 1. They partition the real number line into 4 parts. Use test numbers -3, -1, 0.5, and 2 in each respective part.
For ( , -2), x(x+2)(x-1) < 0.
For (-2,0), x(x+2)(x-1) > 0.
For (0,1), x(x+2)(x-1) < 0.
For (1,  ), x(x+2)(x-1) > 0.
The solution set is then the union (, -2)U (0,1).
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