SOLUTION: Graph the quadratic function given in standard form. f(x)= (x+1)^2-9

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Question 389285: Graph the quadratic function given in standard form.
f(x)= (x+1)^2-9
Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) About Me  (Show Source):
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi,         

f(x)= (x+1)^2-9

given in vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

vertex is Pt(-1,-9)

x- intercepts for which f(x) = 0

0 = (x+1)^2-9

 9 = (x+1)^2

 ± 3 = x+1  x = (3-1)= 2 or  x = (-36-1)= -4

x- intercepts: Pt(-4,0)  and Pt(-2,0)