Question 388348: 1 Use the discriminant to determine whether the quadratic equation has two unequal real solutions, a repeated real solution, or no real solution without solving the equation.
5x2 - 2x - 1 = 0
repeated real solution
two unequal real solutions
no real solution
2 Write the general form of the equation of the circle with radius r and center (h, k).
r = 2; (h, k) = (4, -4)
x2 + y2 + 8x - 8y + 20 = 0
x2 + y2 + 8x + 8y + 20 = 0
x2 + y2 - 8x - 8y + 20 = 0
x2 + y2 - 8x + 8y + 20 = 0
3 Write the standard form of the equation of the circle with radius r and center (h, k).
r = 10; (h, k) = (4, -10)
(x + 4)2 + (y - 10)2 = 100
(x + 4)2 + (y - 10)2 = 10
(x - 4)2 + (y + 10)2 = 100
(x - 4)2 + (y + 10)2 = 10
Found 2 solutions by user_dude2008, stanbon:
Answer by user_dude2008(1862)   (Show Source):
You can put this solution on YOUR website! 1
Answer: two unequal real solutions
2
(x-4)^2+(y+4)^2=4
x^2-8x+16+y^2+8y+16-4=0
x^2+y^2-8x+8y+28=0
3
Answer: (x - 4)2 + (y + 10)2 = 100
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1 Use the discriminant to determine whether the quadratic equation has two unequal real solutions, a repeated real solution, or no real solution without solving the equation.
5x2 - 2x - 1 = 0
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b^2-4ac = 2^2-4*5*-1 > 0, so there are 2 unequal Real Number solutions.
repeated real solution
two unequal real solutions
no real solution
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2 Write the general form of the equation of the circle with radius r and center (h, k).
r = 2; (h, k) = (4, -4)
----
(x-4)^2 + (y+4) = 2^2
x^2-8x+16 + y^2+8y+16 = 4
x^2 + y^2 -8x+8y + 28 = 0
==========================
x2 + y2 + 8x - 8y + 20 = 0
x2 + y2 + 8x + 8y + 20 = 0
x2 + y2 - 8x - 8y + 20 = 0
x2 + y2 - 8x + 8y + 20 = 0
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3 Write the standard form of the equation of the circle with radius r and center (h, k).
r = 10; (h, k) = (4, -10)
(x-4)^2 + (y+10)^2 = 100
===============================
(x + 4)2 + (y - 10)2 = 100
(x + 4)2 + (y - 10)2 = 10
(x - 4)2 + (y + 10)2 = 100
(x - 4)2 + (y + 10)2 = 10
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Cheers,
Stan H.
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