SOLUTION: ``Hi.Can you please help me with this problem? I need to: Graph this inequality: -x^2 + 12x -36>y Thank you so much!''.

Algebra ->  Graphs -> SOLUTION: ``Hi.Can you please help me with this problem? I need to: Graph this inequality: -x^2 + 12x -36>y Thank you so much!''.       Log On


   

Question 381780: ``Hi.Can you please help me with this problem? I need to:
Graph this inequality:
-x^2 + 12x -36>y
Thank you so much!''.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi, 

the vertex form of a parabola, y=a%28x-h%29%5E2+%2Bk where(h,k) is the vertex

y < -x^2 + 12x -36

y < -1(x^2 - 12x + 36)

y < -1(x-6)^2  vertex is Pt(6,0) a = -1 ( a is negative so parabola opens downward




 
Solved by pluggable solver: Plot Any Inequality


Graphing function y%3C-x%5E2%2B12x-36: 

  

  graph%28+300%2C+300%2C+-10%2C+10%2C+-8%2C+12%2C+y%3C-x%5E2%2B12x-36+%29