SOLUTION: One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Write the letter of the larger number.
a.17
b.5
c.34
d.7
Algebra ->
Graphs
-> SOLUTION: One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Write the letter of the larger number.
a.17
b.5
c.34
d.7
Log On
Question 37717: One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Write the letter of the larger number.
a.17
b.5
c.34
d.7
You can put this solution on YOUR website! First...
One number (n) is 12 more than another (n+12).
The sum of the smaller number (n)
and twice the larger number + 2(n+12)
is 39 (=39)
So lets put that formula together.
n + 2(n + 12) = 39
Distribute...
n + 2n + 24 = 39
Subtract 24 from each side...
n + 2n = 15
Add like terms...
3n = 15
Divide both sides by 3...
n = 5
So, the smaller number (n) = 5
The larger number (n + 12) = 17
The correct answer is... a. 17
(