SOLUTION: Please help me solve this equation: Find equations of the tangents to the curve {{{ x = 3t^2+1 }}}, {{{ y=2t^3+1 }}} that pass through the point (4,3).

Algebra ->  Graphs -> SOLUTION: Please help me solve this equation: Find equations of the tangents to the curve {{{ x = 3t^2+1 }}}, {{{ y=2t^3+1 }}} that pass through the point (4,3).      Log On


   

Question 366017: Please help me solve this equation:
Find equations of the tangents to the curve +x+=+3t%5E2%2B1+, +y=2t%5E3%2B1+ that pass through the point (4,3).
Answer by Jk22(389) About Me  (Show Source):
You can put this solution on YOUR website!
from (x,y) = (4,3)

we find t = 1

the tangent slope is dy/dx = 6tē/6t = 1 for t = 1

then tangent equation is : y = x - 1 at (4,3), or y = t - 1, x = t