Hi,
***General point-slope from of an equation is
y = mx + b where m is the slope and b is the value of y where the line crosses the y-axis
Slope of this line 1s -2/3
( perpendicular lines have slopes that are negativie reciprocals of one another)
-2/3 is the negative reciprocal of 3/2
y = (-2/3)x + b
Using ordered pair (6,-3) to solve for b
-3 = (-2/3)*6 + b
-3 + 4 = b
1 = b
y = (-2/3)x + 1