Question 360298: Solve the inequality x(x + 3) > 4. Give your solution in interval notation, using INF for infinity. Found 2 solutions by robertb, edjones:Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! , , .
The critical values of the inequality are 1 and -4.
Choose any number less than -4: pick -5. Now . Therefore (, -5) is part of the solution set.
Choose any number between -4 and 1: pick 0. Now . Therefore (-4, 1) is not part of the solution set.
Choose any number greater than 1: pick 2. Now . Therefore (1, ) is part of the solution set.
The critical values themselves don't satisfy the original inequality. Therefore the solution set is (, -5)U(1,).
You can put this solution on YOUR website! x(x + 3) > 4
x^2+3x-4=0 First find the zeros.
(x+4)(x-1)=0
x=-4, x=1
Test on either side of these numbers.
x=-5: -5(-5+3)=10>4
x=0: 0<4
X=2: 2(2+3)=10>4
.
(-INF, -4)U(1, INF)
.
Ed