SOLUTION: find an equation for a circle satisfying the given conditions center(6,-5) passes through (1,7)

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Question 35736: find an equation for a circle satisfying the given conditions
center(6,-5) passes through (1,7)
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
To find the equation of a circle, you must know the center and the radius of the circle. In this problem, you are given the center, but not the radius. However, the radius is the distance between the center and the given point that is on the circle. Use the distance formula to find this distance, which is the radius of the circle.

r+=+sqrt%28+%281-6%29%5E2+%2B+%287-%28-5%29%29%5E2%29+
+r+=+sqrt%2825%2B+144%29+
r=+sqrt%28169%29+
+r=+13

Now, the equation of a circle with center at (h,k) and radius r is given by
+%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2

In this case, it will be
+%28x-6%29%5E2+%2B+%28y%2B5%29%5E2+=+13%5E2
+%28x-6%29%5E2+%2B+%28y%2B5%29%5E2+=+169

Some teachers require you to multiply this out, but this form is acceptable to me. If your teacher wants it multiplied out, then by all means multiply away!!

R^2 at SCC