SOLUTION: find the vertex of the x and y coordinate, line of symmetry and maximum of f(x) f(x)=-2x^2+2x+7

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Question 356772: find the vertex of the x and y coordinate, line of symmetry and maximum of f(x)
f(x)=-2x^2+2x+7

Found 2 solutions by CharlesG2, Edwin McCravy:
Answer by CharlesG2(834) About Me  (Show Source):
You can put this solution on YOUR website!
find the vertex of the x and y coordinate, line of symmetry and maximum of f(x)
f(x)=-2x^2+2x+7


f(x) = -2x^2 + 2x + 7, this is of form f(x) = ax^2 + bx + c
a = -2, a < 0, so parabola opens downwards

f(x) = -2x^2 + 2x + 7 is standard form of the parabolic equation
converting to vertex form
f(x) = -2(x^2 - x) + 7
(-1/2)^2 = 1/4
-2 * 1/4 = -2/4 = -1/2
7 + 1/2 = 7 1/2 = 15/2
the above 3 lines were completing the square to get below line
f(x) = -2x^2 + 2x - 1/2 + 7 + 1/2 = -2(x^2 - x + 1/4) + 15/2
f(x) = -2(x - 1/2)^2 + 15/2

this is now in vertex form of f(x) = a(x - h)^2 + k, where (h,k) is vertex

vertex is (1/2,15/2)

axis of symmetry -> x = h = 1/2

maximum of f(x) since parabola opens downwards is k or 15/2



Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
find the vertex of the x and y coordinate, line of symmetry and maximum of f(x)
f(x)=-2x^2+2x+7.
There are two methods, {1) completing the square using the memorized
standard form f(x) = ax²+b+c 

and 

(2) using the vertex formula that you have memorized.

-----------------------------------------

Method (1)

f(x) = -2x² + 2x + 7

Factor out -2 from the first two terms:

f(x) = -2(x² - x) + 7

To the side multiply the coefficient of x, which is -1, by 1%2F2 getting
-1%2F2 then squaring -1%2F2 getting %28-1%2F2%29%5E2 or 1%2F4.  Then
adding that and subtracting that inside of the parentheses:

f(x) = -2(x² - x + 1%2F4 - 1%2F4) + 7

Change the parentheses to brackets (so you can put parentheses inside):

f(x) = -2[x² - x + 1%2F4 - 1%2F4] + 7

Factor the first three terms inside the brackets:

f(x) = -2[(x - 1%2F2)(x - 1%2F2) - 1%2F4] + 7

Since those factors in parentheses are the same we write them
as a perfect square:

f(x) = -2[(x - 1%2F2)² - 1%2F4] + 7
 
Now remove the brackets by using the distributive
principle.  That is, we multiply the -2 by putting
it in front of the (x - 1%2F4)^2 and we multiply
the -2 also by the -1%2F2 getting -1. So we have

f(x) = -2(x - 1%2F2)² + 1%2F2 + 7

Then we combine the two terms on the right side and get

f(x) = -2(x - 1%2F2)² + 1%2F2 + 14%2F2

f(x) = -2(x - 1%2F2)² + 15%2F2
  
We recognize this as in the standard form we have memorized:

f(x) = a(x - h)² + k

we know that a = -2, h = 1%2F2 and k = 15%2F2

So that the vertex is (h,k) or (1%2F2, 15%2F2) 

----------------

Method (2), using the vertex formula we have memorized:

x-coordinate of vertex = -b%2F%282a%29

y-coordinate of vertex = what you get when you substitute the
x-coordinate for x in the equation and simplify.

f(x) = -2x² + 2x + 7

Compare to the general form we have memorized,

f(x) = ax² + bx + c

a = -2, b = 2, c = 7

x-coordinate of vertex = -b%2F%282a%29 = -%282%29%2F%282%28-2%29%29 = 
%28-2%29%2F%28-4%29 = 1%2F2

y-coordinate of vertex = what we get when you substitute the
x-coordinate, 1%2F2 for x in the equation and simplify:

f(1%2F2) = -2(1%2F2² + 21%2F2 + 7 = -2(1%2F4) + 1 + 7 = -1%2F2 + 8 = -1%2F2 + 16%2F2 = 15%2F2

so the vertex is the point V(1%2F2, 15%2F2).

-------

No that we have found the vertex by either of the above two methods,

we plot that point and draw a verticle line, the line of symmetry,
through it, like this line drawn in green:



That green line of symmetry has the equation x = 1%2F2 because
every point on that green line of symmetry has 1%2F2 as its 
x-coordinate.

Now we can get some other points on that graph:

 x| y
-----
-2|-5 
-1| 3
 0| 7
 1| 7
 2| 3



And the graph is



The maximum value is the greatest y-value on the graph, which is the
y-coordinate of the vertex, 15%2F2


Edwin