SOLUTION: how do you solve 3a+7 < 16 how do you solve 16 < 3q+4 how do you solve 20-3s > 7s how do you solve 3x > -9

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Question 34984: how do you solve 3a+7 < 16
how do you solve 16 < 3q+4
how do you solve 20-3s > 7s
how do you solve 3x > -9
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
I'll do numbers 1 and 3 then you can use these as a guide to solve the others!
1)
3a%2B7%3C16 Subtract 7 from both sides of the inequality.
3a%3C9 Divide both sides by 3.
a%3C3
3)
20-3s%3E7s Add 3s to both sides of the inequality.
20%3E10s Divide both sides by 10.
2%3Es ors%3C2