SOLUTION: A line is tangent to the circle whose equation is x^+y^+6x-6y-2=0 at the point (1,5). Find the Slope-intercept form of the tangent line.
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-> SOLUTION: A line is tangent to the circle whose equation is x^+y^+6x-6y-2=0 at the point (1,5). Find the Slope-intercept form of the tangent line.
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Question 34924: A line is tangent to the circle whose equation is x^+y^+6x-6y-2=0 at the point (1,5). Find the Slope-intercept form of the tangent line.
Can you help?? Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! A line is tangent to the circle whose equation is x^+y^+6x-6y-2=0 at the point (1,5). Find the Slope-intercept form of the tangent line.
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I THINK YOU MEAN
LET S=x^2+y^2+6x-6y-2=0 at the point (1,5). Find the Slope-intercept form of the tangent line...PLEASE TYPE PROPERLY....ASSUMING SO THE EQN.OF TANGENT AT (X1,Y1)
ON THE CIRCLE IS GIVEN BY S1=0..SO
XX1+YY1+3(X+X1)-3(Y+Y1)-2=0
X+5Y+3(X+1)-3(Y+5)-2=0
4X+2Y-14=0
Y=-2X+7....IS THE EQN. OF TANGENT
