SOLUTION: I have tried so many different things on this problem, thinking through why they would be what they are and I still got them wrong. Please help me understand. This is what I put fo

Algebra ->  Graphs -> SOLUTION: I have tried so many different things on this problem, thinking through why they would be what they are and I still got them wrong. Please help me understand. This is what I put fo      Log On


   



Question 347657: I have tried so many different things on this problem, thinking through why they would be what they are and I still got them wrong. Please help me understand. This is what I put for each in order, it is what I was convinced the answer was. (F,T,T,F,F,F,F) Why are any of these wrong?
(1 pt) Let the function f be defined by f(x) = {1}/{sqrt{1-x^2}}. Indicate whether the following statements are True (T) or False (F). You must get all answers correct in order to receive credit.
___1. f(x) is never positive.
___2. 1 is in the domain of f
___3. 0 is in the domain of f
___4. f(x) is never negative.
___5. All negative real numbers are in the domain of f
___6. f(x) is never zero.
___7. All positive real numbers are in the domain of f

Found 2 solutions by edjones, jim_thompson5910:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=1/sqrt(1-x^2)
.
2.
1-x^2>0 If it is zero then there is division by zero which is not allowed. If it is less than zero then the denominator is an imaginary number, also not allowed.
-x^2>-1
x^2<1
-1%3Cx%3C1
2 is F
.
The rest of your answers are correct.
.
Ed

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
1. f(x) is never positive.

This is false since sqrt%281-x%5E2%29 is always nonnegative.
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2. 1 is in the domain of f
This is false since x=1 makes the denominator equal to zero.

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3. 0 is in the domain of f

This is true since the input x=0 yields a real number output.
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4. f(x) is never negative.

This is true since sqrt%281-x%5E2%29 is always nonnegative.
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5. All negative real numbers are in the domain of f

False. The domain is -1%3Cx%3C1. So clearly, a number like x=-10 is NOT in the domain.
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6. f(x) is never zero.

This is true as the numerator will never equal zero.

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7. All positive real numbers are in the domain of f

False. Again, the domain is -1%3Cx%3C1



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Jim