SOLUTION: I am not sure if I am plugging in my test points correctly. FOr example on y<-x+1 I substituted 0 for x and y which gave me the answer 0<-1. I assume I should change that to 1>0

Algebra ->  Graphs -> SOLUTION: I am not sure if I am plugging in my test points correctly. FOr example on y<-x+1 I substituted 0 for x and y which gave me the answer 0<-1. I assume I should change that to 1>0       Log On


   



Question 342390: I am not sure if I am plugging in my test points correctly. FOr example on y<-x+1 I substituted 0 for x and y which gave me the answer 0<-1. I assume I should change that to 1>0 to put the x on the left side of the inequality? Is that correct? Can you just show me how you would work this, how you would enter test points and what the graph should look like in the end?
Thanks,

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If you plug in x=0 and y=0 into y < -x+1, you'll get 0 < 1 which is indeed true. Since the inequality is true for (0,0), this means that you shade the entire region that contains (0,0) (ie shade below the line). Note: Make sure that the boundary line is a dotted/dashed line.


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