SOLUTION: can you write an equation of the line containing the given point and perpendicular to the given line; (6,-5); 2x+2y=5

Algebra ->  Graphs -> SOLUTION: can you write an equation of the line containing the given point and perpendicular to the given line; (6,-5); 2x+2y=5      Log On


   



Question 338780: can you write an equation of the line containing the given point and perpendicular to the given line; (6,-5); 2x+2y=5
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
(6,-5);
2x+2y=5
add -2x
2x-2x+2y=-2x +5
2y= -2x+5
divide by 2
y= -x+5/2
this is of the form
y = mx +b
compare the equations
slope m = -1
.
the require line is perpendicular to this line with slope -1
so the slope will be 1
..
y = mx +b
plug value of (6,-5)
-5=1*6+b
-5=6+b
so b = -11
the required equation will be slope 1 and b = -11
y=x-11
graph%28300%2C300%2C-12%2C12%2C-12%2C12%2C-x%2B%285%2F2%29%2Cx-11%29