SOLUTION: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol?
Algebra ->
Graphs
-> SOLUTION: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol?
Log On
Question 323879: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol? Answer by nyc_function(2741) (Show Source):
You can put this solution on YOUR website! Let L = liters
0.40L + 10(0.80) = 0.60(L + 10)
The above equation is all you need to find the answer.
