SOLUTION: solve the parabola y=-1/2(x-1)^2 + 2 i got the direction which is down, vertex (-1,2), aos x=-1, the y intercept -2.5 but i need help getting the x intercept

Algebra ->  Graphs -> SOLUTION: solve the parabola y=-1/2(x-1)^2 + 2 i got the direction which is down, vertex (-1,2), aos x=-1, the y intercept -2.5 but i need help getting the x intercept      Log On


   

Question 32223: solve the parabola
y=-1/2(x-1)^2 + 2
i got the direction which is down, vertex (-1,2), aos x=-1, the y intercept -2.5 but i need help getting the x intercept
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
The x-intercepts can be found by setting y = 0 and solving for x.
0+=+-%281%2F2%29%28x-1%29%5E2+%2B+2 Solve for x. Subtract-%281%2F2%29%28x-1%29%5E2 from both sides of the equation.
%281%2F2%29%28x-1%29%5E2+=+2 Multiply both sides by 2.
%28x-1%29%5E2+=+4 Take the sqare root of both sides.
x-1+=+2 That's + or - 2. Now add 1 to both sides.
x+=+1%2B-2
The x-intercepts are:
x = 1+2 = 3
x = 1-2 = -1