SOLUTION: How do you graph this inequality? y<-x/3

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Question 29727: How do you graph this inequality?
y<-x/3
Answer by Cintchr(481) About Me  (Show Source):
You can put this solution on YOUR website!
+y+%3C+-1x%2F3+%2B+0+ in point slope form.
slope = m = -1/3
y-int = b = 0
your first point is the origin, since the intercept is 0
using the slope of -1/3 .... go DOWN one point and then to the right 3 points
you should now be at (3,-1)
starting back at the origin ... go UP 1 and to the left 3
you should now be at (-3, 1)
Draw the line that connects the three points.
since this is NOT and equality, the line is dotted, not solid.
chose a point NOT on the line ... such as (1,1) plug it in to the equation.
+y+%3C+-1x%2F3+%2B+0+
+1+%3C+-1%281%29%2F3+
+1+%3C+-1%2F3+ this is a FALSE statement.
shade the other side of the line.