SOLUTION: The perimter of a rectangle is 174 inches. The elngth exceeds the width by 61 inches. What is the length and the width? What is the lenghth?______ (Type and integer or a decimal

Algebra ->  Graphs -> SOLUTION: The perimter of a rectangle is 174 inches. The elngth exceeds the width by 61 inches. What is the length and the width? What is the lenghth?______ (Type and integer or a decimal      Log On


   



Question 291095: The perimter of a rectangle is 174 inches. The elngth exceeds the width by 61 inches. What is the length and the width?
What is the lenghth?______
(Type and integer or a decimal)
What is the width?_____
( type and integer or a decimal)

Answer by brucewill(101) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = width
Therefore, x + 61 = length.
Permiter requires 2 each of width & length.
2x + 2(x + 61) = 174
2x + 2x + 122 = 174
4x = 52
highlight%28x+=+13%29 width
Therefore, 13 + 61 = 74 length.
Check: 13 + 74 + 13 + 74 = 174. OK.