You can put this solution on YOUR website! First, get the main equation into slope-intercept form: y = mx + b
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3x -y = 8
-y = -3x +8
y = 3x - 8
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Second, you recall that any line with slope = 3 will be parallel to this line.
Your problem is define such a line that goes through the point (7,2).
Well, plug x=7 into the equation and then adjust 'b' to make y=2.
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y = 3x -b
2 = 3(7) -b
2 = 21 -b
-19 = -b
b = 19
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so,
y = 3x -19 will be parallel and will go through the point.
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Check by graphing the two equations. y=3x-8 is red; y=3x-19 is green.
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Rechecking the question, this equation needs to be shown in slope-intercept and in standard form.
y = 3x-19 :: slope-intercept form
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Standard form is: Ax + By = C
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subtract 3x from both sides
-3x + y = -19
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multiply both sides by -1
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3x -y = 19 :: standard form
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Done
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