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Question 27889: 12. Solve each of the following systems by addition. If a unique solution does not exist, state whether the system is inconsistent or dependent.
2x + 3y = 1
5x + 3y = 16
Answer by AnlytcPhil(1806) (Show Source):
You can put this solution on YOUR website! Solve each of the following systems by addition.
If a unique solution does not exist, state whether the
system is inconsistent or dependent.
2x + 3y = 1
5x + 3y = 16
To make the y's cancel, get the LCM of their coefficients
3 and 3 which is 3. Multiply the first equation through by 1
to keep 3y as it is. Multiply the second equation through by
-1 to make it become -3y
1[2x + 3y = 1]
-1[5x + 3y = 16]
Don't forget to multiply BOTH SIDES, not just the left side.
2x + 3y = 1
-5x - 3y = -16
Now we add those vertically:
2x + 3y = 1
-5x - 3y = -16
—————————————————
-3x = -15
x = 5
2x + 3y = 1
5x + 3y = 16
To make the x's cancel, get the LCM of their coefficients
2 and 5 which is 10. Multiply the first equation through by
5 to make 2x become 10x. Multiply the second equation
through by by -2 to make it become -10x
5[2x + 3y = 1]
-2[5x + 3y = 16]
Afain, don't forget to multiply BOTH SIDES, not just the left side.
10x + 15y = 5
-10x - 6y = -32
Now we add those vertically:
10x + 15y = 5
-10x - 6y = -32
—————————————————
9y = -27
y = -3
Edwin
AnlytcPhil@aol.com
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