SOLUTION: I have to put this equation y=x^2-2x-15 into this form y=a(x-h)^2+k. I have to find the line of symmetry. (h,k)=vertex I think you use complete the square technique. Please help. t
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-> SOLUTION: I have to put this equation y=x^2-2x-15 into this form y=a(x-h)^2+k. I have to find the line of symmetry. (h,k)=vertex I think you use complete the square technique. Please help. t
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Question 27694: I have to put this equation y=x^2-2x-15 into this form y=a(x-h)^2+k. I have to find the line of symmetry. (h,k)=vertex I think you use complete the square technique. Please help. thanks Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website! I have to put this equation y=x^2-2x-15 into this form y=a(x-h)^2+k.
MAKE A PERFECT SQUARE USING X^2 AND X TERMS.ADD AND SUBTRACT THE REQUIRED CONSTANT FOR THE PURPOSE.
Y=(X-1)^2-1-15=(X-1)^2-16...COMPARING WITH THE ABOVE
y=a(x-h)^2+k.
WE GET A=1 AND K=-16
I have to find the line of symmetry.
X-1=0 IS THE LINE OF SYMMETRY SINCE ON EITHER SIDE OF X=1,WE GET SYMMETRIC/SAME VALUES FOR Y..AT X=1+2=3..Y IS -12 AND AT X=1-2=-1 ALSO WE GET Y=-12
(h,k)=vertex I think you use complete the square technique.
YA ..THE VERTEX AS YOU SHOULD KNOW NOW IS AT X=1 AND AT X=1 ,Y=-16 .SO (1,-16) IS THE VERTEX
THE VCGRAPH WILL LOOK LIKE THIS
Please help. thanks
